Question

2/5(10y-3) =1 what is a answer​

Answer 1

$\huge\mathfrak{Solution}$

$2/5(10y-3)=1$

$4y-6/5=1$

$(20y-6)/5=1$

$20y-5=1×5$

$20y-5=5$

$20y=5+5$

$y=10/20$

$y=1/2$

$\boxed{\underline{\tt{\:math{\:Hence,the\:answer\:is\:1/2}}}}$

Answer 2

$\sf\Large{\underline{\underline{Question:-}}}$

$\sf\Large\frac{2}{5} \: (10y - 3) \: = \: 1$

Find the value of y.

$\sf\Large{\underline{\underline{Solution:-}}}$

Given:-

$\sf\Large\frac{2}{5} \: (10y - 3) \: = \: 1$

To find:-

The value of y.

Here,

$\sf\Large\frac{2}{5} \: (10y - 3) \: = \: 1$

$\sf\Large\implies\frac{2}{\cancel{5}} × \cancel{10} \: y - \frac{6}{5} = 1$

$\sf\Large\implies \: 4y - \frac{6}{5} = 1$

$\sf\Large\implies \: 4y = 1 + \frac{6}{5}$

$\sf\Large\implies \: 4y = \frac{11}{5}$

$\sf\Large\implies \: y = \frac{11}{5} × \frac{1}{4}$

$\sf\Large{\boxed{y = \frac{11}{20}}}$

$\sf\red{\boxed{Hence \: the \: value \: of \: y = \frac{11}{20}}}$

$\pink{Hope \: it \: helps}$