Question

2,5/2,3,7/3,... are in A.P. OR NOT

Answer 1

for any no.s to be in A.P. diffence in consecutive no.s must be same
so,5/2 - 2=1/2
and 7/3 - 5/2 = -1/6 which is unequal to 1/2
so they are not in AP

Answer 2

For a series to be an AP they must have a common difference

5/2-2 = 1/2
3-5/2 = 1/2 which satisfies till here... But you've gotta checl ALL the terms, right?

So,
7/3-3 = -2/9 which isn't following the rule of having a common difference here.

The given series isn't an AP