Math, asked by murtazavali2007, 4 months ago

(2/5)² × (5/2)^-7 = (2/5)^2x-1


find the value of x

Answers

Answered by talalhaider37
0

Answer:

x=5

Step-by-step explanation:

(2/5)^2× (5/2)^-7=(2/5)^2x-1

(2/5)^2 ×(2/5)^7=(2/5)^2x-1  (by changing the order)

as base are same so exponents can be added

(2/5)^9=(2/5)^2x-1

by considering exponents  on both sides

9=2x-1

2x=10

x=5

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