Question

(2+√5)⅓ +(2-√5)⅓ = N
Find N

Answer 1

on cubic both sides

(2+√5) power 1/3×3+ (2-√5) power 1/3×3=N ki power 3

2+√5+2-√5=n ki power 3

4= n ki power 3

surd 4 = n

Answer 2

n =

$\sqrt[3]{2 + \sqrt{5} } + (2 - \sqrt{5} ) {}^{ \frac{1}{3} }$