2√5^2 - 7x - 3√5 factorise
Answers
Answered by
0
Answer:
Given,
2x2+7x+52=0
or, 2x2+2x+5x+52=0
or, x2(x+2)+5(x+2)=0
or, (x2+5)(x+2)=0
⇒x=−25,−2.
These are the required roots.
Similar questions