(2/5)^2x+6×(2/5)^3=(2/5)^x+2 find the value of x
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Answer:
Given, 2x−5=3(x−5)
⇒2x−5=3x−15
Transpose x terms on one side, we get
3x−2x=−5+15
⇒x=10
Therefore, value of x is 10.
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