(2/5)^-3*(2/5)^+15 = (2/5)^2+3x
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(2/5)^-3 × (2/5)^15 = (2/5)^2 + 3x
=> (2/5)^-3+15 = (2/5)^2 + 3x
=> (2/5)^+12 = (2/5)^2 + 3x
=> 12 = 2+ 3x (2/5 is cancelled on both sides)
=> 2+3x = 12
=> 3x = 12- 2
=> 3x = 10
=> x = 10/3
=> x = 3.333....
I hope it helps you.
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