Question

(2/5)^-3 × (2/5)^3 × = (2/5)^2+3x
​

Answer 1

$\huge\mathtt\red{Question}$

$( \frac{2}{5} )^{ - 3} \times {( \frac{2}{5} )}^{3} = {( \frac{2}{5}) }^{2} + 3x$

$\huge\mathtt\red{Process}$

$\longrightarrow$ To find the answer you have to solve it by simple simplification method.

$\longrightarrow$ Firstly, as we know that if the base are same and the condition is to multiply then the powers will be added.

$\longrightarrow$ Secondly, separating the variable from the constant.

$\longrightarrow$ By doing the simplification we will get the answer.

$\huge\mathtt\red{Solution}$

$( \frac{2}{5} )^{ - 3} \times {( \frac{2}{5} )}^{3} = {( \frac{2}{5}) }^{2} + 3x \\ → \frac{2}{5} ^{ - 3 + 3} = { (\frac{2}{5}) }^{2} + 3x \\ → \frac{2}{5} ^{0} = {( \frac{2}{5} )}^{2} + 3x \\ →1 = \frac{4}{25} + 3x \\exchanging \: the \: sides \\ → \frac{4}{25} + 3x = 1 \\ →3x = 1 - \frac{4}{25} \\ →3x = \frac{25 - 4}{25} \\ →3x = \frac{21}{25} \\ →x = \frac{21}{25} \times \frac{1}{3} \\ →x = \frac{7}{25}$

$\huge\mathtt\red{Answer}$

$\boxed{x=\frac{7}{25}}$