Math, asked by arjunnain1508, 2 months ago

2√5 + √3 + 2√5 - √3. = a + √15b
________ ________
2√5 - √3 2√5 + √4


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Answers

Answered by IIMissTwinkleStarII
3

Answer:

REFER TO AS ATTACHMENT

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Answered by rishabh994
2

Step-by-step explanation:

 \frac{2 \sqrt{5}  +  \sqrt{3}  }{2 \sqrt{5} -  \sqrt{3}  }  +  \frac{2 \sqrt{5} -  \sqrt{3}  }{2 \sqrt{5} +  \sqrt{3}  }  = a +  \sqrt{15} b

 \frac{2 \sqrt{5}  +  \sqrt{3}  }{2 \sqrt{5} -  \sqrt{3}  }   \times \frac{2 \sqrt{5}  +  \sqrt{3}  }{2 \sqrt{5}  +  \sqrt{3}  } +  \frac{2 \sqrt{5} -  \sqrt{3}  }{2 \sqrt{5} +  \sqrt{3}  } \times \frac{2 \sqrt{5}   -   \sqrt{3}  }{2 \sqrt{5} -  \sqrt{3}  }

 \frac{(2 \sqrt{5 }  +  \sqrt{3})^{2}  +  {(2 \sqrt{5}  -  \sqrt{3}) }^{2}  }{ {(2 \sqrt{5}) }^{2}  -  {( \sqrt{3}) }^{2} }

 \frac{20 + 3 + 2 \times 2 \sqrt{5} \times  \sqrt{3}  + 20 + 3 - 2 \times 2 \sqrt{5}  \times  \sqrt{3}  }{20 - 3}

 \frac{46}{17}

a =  \frac{46}{17} and \: b = 0

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