2/5^-3 × 2/5^5 please tell me how to solve
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(2/5)^-3*(2/5)^5
a^m*a^n = a^m + n (According to laws of exponents)
(2/5)^-3 + 5
(2/5)^2
= 4/25
Hope it helps :)
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AKSHATGUPTA3624:
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