Math, asked by ritikasingh28073, 1 month ago

2.5,3.5,15,72,352,? find missing no.?​

Answers

Answered by Abhijeet1589
1

The missing number is 1885.

GIVEN

Number series- 2.5,3.5,15,72,352,?

TO FIND

The missing number.

SOLUTION

We can simply solve the above problem as follows;

We are given a number series; 2.5,3.5,15,72,352, ?

Form the above series we can make out the pattern applied to form the series as;

2.5 × 1 + (1)³ = 3.5

3.5 × 2 + (2)³ = 15

15 × 3 + (3)³ = 72

72 × 4 + (4)³ = 352

So,

The 6th number in the series will be 5 multiples by 5 and adding the result to the cube of 5

Therefore,

352 × 5 + (5)³ = 1885.

Hence, The missing number is 1885.

#Spj2

Answered by syed2020ashaels
0

Answer:

The answer to the given question is the series after replacing the? is 2.5,3.5,15,72,352,1885

Step-by-step explanation:

Given:

2.5,3.5,15,72,352,?

to find :

Find the number that should replace the?.

Solution :

The series consists of different numbers 2.5,3.5,15,72,352,?

The next number in the series has to be found.

From the above series, we have to find the pattern applied to all the numbers to form the series.

Let us find the pattern or logic for the numbers in the series.

2.5 \times 1 +  {(1)}^{3}  = 2.5 + 1 = 3.5

The above result is the second term

3.5  \times 2 +  {2}^{3}   \\ =  7  + 8 \\  = 15

The result is the next term.,

15 \times 3 +  {3}^{3}   \\  = 45 + 27 \\  = 72

The next term will be obtained by

72 \times 4 +  {4}^{3}  \\  = 288 + 64 \\  = 352

The next term will be obtained by

352 \times 5 +  {5}^{3}  \\  = 1760 + 125 \\  = 1885

The value obtained is 1885.

Therefore, the final answer to the given question is 2.5,3.5,15,72,352,1885.

# spj5

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