2%5×{_3%7}_1%6×3%2+1%14×2%5
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Given:
simplify 2/5×-(3/7)-1/6×3/2+1/14×2/5
Rearranging the terms , we get
= [2/5 ×(-3/7)+(1/14)(2/5)]-1/6×3/2
= (2/5)[ -3/7 +1/14] - 1/4
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By Distributive property:
A×B + A×C = A(B+C)
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=(2/5) [ (-6+1)/14] - 1/4
= (2/5)×(-5/14) - 1/4
= -1/7 - 1/4 /* After cancellation */
=( -4 - 7)/28
= -11/28
Therefore,
2/5×-(3/7)-1/6×3/2+1/14×2/5
= -11/28
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