Question

2\5×{_3\7_1\6×3\2+1\14×2\5

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{2}{5}( - \frac{3}{7} - \frac{1}{6} \times \frac{3}{2} + \frac{1}{14} \times \frac{2}{5} ) \\ \\ = \frac{2}{5} ( - \frac{3}{7} - \frac{1}{2} \times \frac{1}{2} + \frac{1}{7} \times \frac{1}{5} ) \\ \\ = \frac{2}{5} ( - \frac{3}{7} - \frac{1}{4} + \frac{1}{35} ) \\ \\ \\ \\ = \frac{2}{5} ( \frac{ - 3 \times 20 - 1 \times 35 + 1 \times 4}{140}) \\ \\ = \frac{2}{5} ( \frac{ - 60 - 35 + 4}{140} ) \\ \\ = \frac{2 }{5} ( \frac{ - 95 + 4}{140} ) \\ \\ = \frac{2}{5} \times \frac{ - 91}{140} \\ \\ = \frac{1}{5} \times \frac{ - 91}{70} \\ \\ = \frac{ - 91}{350}$

Hope this helps!!!

@Mahak24

Thanks...
☺☺

Answer 2

$\frac{2}{5} [- \frac{3}{7} - \frac{1}{6} * \frac{3}{2} + \frac{1}{14} * \frac{2}{5}]$

$\frac{2}{5}[- \frac{3}{7} - \frac{1}{2} * \frac{1}{2} + \frac{1}{7} * \frac{1}{5]}$

$\frac{2}{5} [ -\frac{3}{7} - \frac{1}{4}+ \frac{1}{35}]$

$\frac{2}{5}[ -\frac{3}{7}+ \frac{1}{35} - \frac{1}{4}]$

$\frac{2}{5}[ \frac{-15 + 1}{35} - \frac{1}{4}]$

$\frac{2}{5}[ - \frac{14}{35} - \frac{1}{4}]$

$\frac{2}{5}[ \frac{-56 -35}{140}]$

$\frac{2}{5}[ \frac{-91}{140}]$

$\frac{2}{5}$× $( \frac{-91}{140})$

$\frac{1}{5}$× $( \frac{-91}{70} )$

$\frac{-91}{350}$



i hope this will help you



-by ABHAY