Question

(2/5)^3 divided by (4/25)^-6 = (2/5)^ 2a-1

Answer 1

Answer:

a=16

Step-by-step explanation:

${( \frac{2}{5}) }^{3} \div {( \frac{4}{25} )}^{ - 6} = { \frac{2}{5} }^{2a - 1}$

${( \frac{2}{5}) }^{3} \times {( \frac{4}{25} )}^{ 6} = { \frac{2}{5} }^{2a - 1}$

${( \frac{2}{5}) }^{3} \times {( \frac{2}{5} )}^{ 12} = { \frac{2}{5} }^{2a - 1}$

${( \frac{2}{5}) }^{15} = { \frac{2}{5} }^{2a - 1}$

It implies that

$15 = 2a - 1$

$2a = 16 \\ a = 8$