Question

2,5,8,11,....ka 50 pad gyat kijiye

Answer 1

Step-by-step explanation:

Here first term a = 2,

Common Difference d = 3

Number of terms n = 50

We need to find: $t_{50}$

$n^{th}$ term of an AP is given as:

$t_{n}= a +(n-1)d\\</p><p> t_{50}= 2 +(50-1)3\\</p><p> t_{50}= 2 +49\times 3\\</p><p>t_{50}= 2 +147\\</p><p>t_{50}= 149$

Hence, $50^{th}$ term of given AP is 149.