Question

2 + 5 + 8 + ... + (3n-1) = n (3n+1) /2

Answer 1

$\bold\red{♡Answer♡}$

Nth term = 3n-1

Now to find sum of n terms

Sum = summation tn

sum of n natural numbers = n(n+1)/2

Sum=summation tn

=3(n(n+1)/2 - n

=(3n²+3n-2n)/2

=3n²+n/2

=n(3n+1)/2

hence proved .

hope it helps.

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Answer 2

Step-by-step explanation:

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