Question

2:5,9:6,12:3and10:4 find the compound propertion​

Answer 1

Step-by-step explanation:

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Find the compounded ratio of:

(i) 2: 3 and 4: 9

(ii) 4: 5, 5: 7 and 9: 11

(iii) (ab):(a+b),(a+b)

2

:(a

2

+b

2

)and(a

4

b

4

):(a

2

b

2

)

2

Medium

Solution

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(i) 2: 3 and 4: 9

We know that

Compound ratio =2/3×4/9

=8/27

=8:27

(ii)4:5,5:7 and 9:11

We know that

Compound ratio =4/5×5/7×9/11

=36/77

=36:77

(iii) (a–b):(a+b),(a+b)

2

:(a

2

+b

2

)and(a

4

–b

4

):(a

2

–b

2

)

2

We know that

Compound ratio =(a–b)/(a+b)×(a+b)

2

/(a

2

+b

2

)×(a

4

–b

4

)/(a

2

–b

2

)

2

By further calculation

=(a–b)/(a+b)×[(a+b)(a+b)]/(a

2

+b

2

)×[(a

2

+b

2

)(a+b)(a–b)]/[(a+b)

2

(a–b)

2

]

So we get

=1/1

=1:1