Question

2.5 g of Ethnoic acid is dissolved in 75 g of Benzene . Calculate the molality

Answer 1

Heya mate here is your answer
w of CH3COOH=2.5 gm

mol.wt. of CH3COOH= 12+3+12+16 x2 +1=60

w of benzene= 75 gm =0.075 kg

mol.wt. of C6H6= 12 x6 +1 x 6 =78

Molality =wt. of solute/ (mol.wt. of solute x wt. of solvent in kg)

m=2.5/60 x 0.075

m =0.56 mole /kg Ans.