Question

√2×5 how to solve please solve this let me know the answer​

Answer 1

Answer:

IF THE BOTH ARE IN THE ROOT THEN

√2×5 = √10

IF 5 IS OUTSIDE THE ROOT THEN

5√2..

HOPE IT HELPS...

MARK ME AS BRAINIEST

Answer 2

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

⠀●$\tt{\sqrt{\dfrac{2}{5}} }$ ⠀⠀⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

⠀⠀⠀⠀

● solve it.

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

⠀⠀⠀$\tt{\sqrt{\dfrac{2}{5}} }$(Given) ⠀⠀

we can write, $\implies$$\tt{\dfrac{\sqrt{2}}{\sqrt{5}} }$ ⠀

Now multiply, this $\tt{\dfrac{\sqrt{5}}{\sqrt{5}} }$

we get,

$\rightsquigarrow$ $\tt{\dfrac{\sqrt{2}}{\sqrt{5}} }$×$\tt{\dfrac{\sqrt{5}}{\sqrt{5}} }$

$\rightsquigarrow$ $\tt{\dfrac{\sqrt{2}×\sqrt{5}}{\sqrt{5}×\sqrt{5}} }$ ⠀

Raise $\tt{\sqrt{5} }$ to the power of 1.

⠀$\rightsquigarrow$ $\tt{\dfrac{\sqrt{2}\sqrt{5}}{\sqrt{5}^1\sqrt{5}^1} }$ ⠀

we know that,

$\boxed{\underline{\underbrace{\mathcal\color{gold}{a^{m}a^{n}=a^{m+n}}}}}$

:$\rightsquigarrow$ $\tt{\dfrac{\sqrt{2}\sqrt{5}}{\sqrt{5}^{1+1}} }$

:$\rightsquigarrow$ $\tt{\dfrac{\sqrt{2}\sqrt{5}}{\sqrt{5}^{2}} }$

:$\rightsquigarrow$ $\tt{\dfrac{\sqrt{2}\sqrt{5}}{5} }$

:$\rightsquigarrow$ $\tt{\dfrac{\sqrt{2×5}}{5} }$ ⠀

:$\rightsquigarrow$ $\tt{\dfrac{\sqrt{10}}{5} }$ ⠀