2.5 KG of a gas heated from 80°c to 250°c according to constant pressure process.If specific heats are cp=1.005KJ/cal, cv=0.714kg/cal find. 1Heat required 2.change in internal energy 3. work done on the gas
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2.5 kg of a gas heated from 80°C to 250°C according to constant pressure process. If specific heats are Cp = 1.005Kcal/kg/°C , Cv = 0.71 Kcal/kg/°C
We have to find
- heat required
- change in internal energy
- work done on the gas
1. heat required = change in energy at constant pressure
= mCp∆T
= 2.5 kg × 1.005Kcal/Kg/°C × (250 - 80)°C
= 2.5 × 1.005 × 170 Kcal
= 427.125 Kcal
Therefore the heat required is 427.125 Kcal
2. internal energy change = change in energy at constant volume
= mCv∆T
= 2.5 kg × 0.714 Kcal/Kg/°C × (250 - 80)°C
= 2.5 × 0.714 × 170
= 303.45 Kcal
Therefore the change in internal energy is 303.45 Kcal
3. work done on the gas = Q - U
[ from 1st law of thermodynamics]
= (427.125 - 303.45) KCal
= 124.325 Kcal
Therefore work done on the gas is 124.325KCal
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