Question

2.5 kg of water at 20°C is poured into a vessel containing 0.85 kg of ice at 12°C. The result is a mixture of ice and water at 0°C. Calculate the final mass of ice in the vessel. Assume that: Water equivalent of vessel = 0.05 kg specific heat of ice = 2.04 kj/kgk latent heat of fusion = 335 kj/kg specific heat of water = 4.2 kj/kgk.
I need the whole solution... Pls

Answer 1

Answer:

answer your room to be very important and you can see the difference between the two and the other two and a half hour of Duty to make golden the right way to do it again for the rest and a few seconds and the end result of the

$22y2 { { {22 {)333333666}^{?} }^{2} }^{2} }^{2}$

Answer 2

Answer:

Liquid water has one of the highest specific heats among common substances, about 4182 J/(K kg) at 20 °C; but that of ice just below 0 °C is only 2093 J/(K kg).The "X" comes from the Greek letter Chi, which is the first letter of the Greek which became Christ in English. The suffix -mas is from the Latin-derived Old English word for Mass.Specific heat of water at constant volume in j/kgk