Question

2.5 kilogram stone is released from rest and fall towards earth after 4
second magnitude of its Momentum is​

Answer 1

Answer:

Momentum is 100kgs/s is the correct answer

Answer 2

Answer:

100 kg m/s

Explanation:

$\underline{\bigstar\:\textsf{Given:}}$

• Mass (m) = 2.5 kg
• Initial velocity (u) = 0 m/s
• Time (t) = 4 s

$\underline{\bigstar\:\textsf{To\:find:}}$

• Momentum (P) = ?

$\underline{\bigstar\:\textsf{Solution:}}$

We know, $\green{\sf{momentum\:=\:mass(m)\:\times\:velocity(v)}}$

Here, velocity is the final velocity.

We also remember Newton's 1st equation of motion i.e, v = u + at. We can take acceleration as 10 m/s².

$\Longrightarrow$ v = 0 + 10 × 4

$\therefore$ Final velocity of stone = 40 m/s.

Now, just put all the values in the formula.

$\Longrightarrow$ P = 2.5 × 40

$\Longrightarrow\sf{\underline{\underline{\therefore\:Momentum\:=\:100\:kgm/s}}}$