2.5 L of a sample of a gas at 27 degree Celsius and 1 bar pressure is compressed to a volume of 500 ml keeping the temperature constant the percentage increase in pressure is
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Answered by
15
V1= 2.5L , T1= 27 degree C = 300 kelvin , P1= 1 bar
V2= 0.5L, T2= 300 kelvin , P2= ?
V1×P1/T1 = V2×P2/T2
P2 = V1×P1×T2/T1×V2
= (2.5)×(1)×(300)/(300)×(0.5)
= 1.25 bar
So, the percentage increased is 0.25%
V2= 0.5L, T2= 300 kelvin , P2= ?
V1×P1/T1 = V2×P2/T2
P2 = V1×P1×T2/T1×V2
= (2.5)×(1)×(300)/(300)×(0.5)
= 1.25 bar
So, the percentage increased is 0.25%
TheAishtonsageAlvie:
You have made a mistake bro re - edit it
Answered by
58
HEY THERE!!
GIVEN =
SINCE TEMPERATURE IS CONSTANT , WE USE HERE BOYLE' S LAW BECAUSE HERE ONLY T IS CONSTANT
SO
V = 2.5 Litres
P = 1 BAR
v = 500 ml or we can say 0.5 L
p = ?
PV = pv
⇒ 1×2.5 = p × .5
⇒p = 5 bar
Trick for you⇒
TO FIND THE % INCREASES IN PRESSURE USE THE FORMULA
% INCREASE = { Increase in pressure ×100} / initial pressure
⇒( 4 × 100 ) ÷ 1 = 400 %
HENCE 400 % PRESSURE HAS INCREASED
@Dr.Aish
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