Chemistry, asked by chattanilovely3304, 1 year ago

2.5 L of a sample of a gas at 27 degree Celsius and 1 bar pressure is compressed to a volume of 500 ml keeping the temperature constant the percentage increase in pressure is

Answers

Answered by hetnaik
15
V1= 2.5L , T1= 27 degree C = 300 kelvin , P1= 1 bar
V2= 0.5L, T2= 300 kelvin , P2= ?

V1×P1/T1 = V2×P2/T2

P2 = V1×P1×T2/T1×V2
= (2.5)×(1)×(300)/(300)×(0.5)
= 1.25 bar

So, the percentage increased is 0.25%

TheAishtonsageAlvie: You have made a mistake bro re - edit it
Answered by TheAishtonsageAlvie
58

HEY THERE!!

GIVEN =

SINCE TEMPERATURE IS CONSTANT , WE USE HERE BOYLE' S LAW BECAUSE HERE ONLY T IS CONSTANT  


SO


V = 2.5 Litres  

P = 1 BAR

v = 500 ml  or we can say 0.5 L

p =  ?


PV = pv

1×2.5 = p × .5

⇒p = 5 bar

Trick for you⇒

TO FIND THE % INCREASES IN PRESSURE USE THE FORMULA

% INCREASE =   {  Increase in pressure ×100} / initial pressure  

                      ⇒(  4  × 100 )  ÷ 1  = 400 %

HENCE 400 % PRESSURE HAS INCREASED

@Dr.Aish




hetnaik: check your ans bro... you've made mistake
hetnaik: 1×2.5=p×0.5 the ans is 1.25 bar not 5 bar
hetnaik: no..... i am sorry I've made mistake
hetnaik: its a silly mistake bro
TheAishtonsageAlvie: yupp
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