Question

2.5 mJ of work is done in moving a charge of 10^-6 C from one point to another. what is the potential difference between the two points?

Answer 1

Explanation:

The potential difference between the two points is 2.5*10 3 v

Answer 2

Answer:

2500V

Explanation:

Work done,  W=Q x Δv

                    Δv= W/q

                     =    2.5 x 10^-3 J / 10^-6

                  Δv      = 2.5 x 10³

                          =  2500V

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