Math, asked by himanshushukla63, 9 months ago

2/5 of the voters promise to vote for P and the rest promised to vote for Q. Of these, on the last day 25% of the voters went back on their promise vote for P and 15% of the voters went back on their promise to vote for Q and reversed their votes. Q lost by 44 votes. Then the total number of votes is ?​

Answers

Answered by Anonymous
3

Answer:

\huge\underline\bold {Answer:}

Let the total number of voters = x

Promised voters for P = 2/5 of x = 0.4 x

Promised voters for Q = 0.6 x

Numbers of voters who voted for

P = 0.75 × 0.4x + 0.15 × 0.6x

= 0.3x + 0.09x = 0.39x

Number of voters who voted for

Q = 0.85 × 0.6x + 0.25 × 0.4x

= 0.51x + 0.1x = 0.16x

Given, 0.16x – 0.39x = 44

=> 0.22x = 44

=> 44/0.22 = 4400/22 = 200.

Answered by shambhavi02006
2

Answer:

45.

Step-by-step explanation:

Vote for P:-

25/100 × 2/5 = 1

Vote for Q:-

15/100 × 3/5

Votes are reversed... means there is 1 vote for Q and 15/100 × 3/5 votes for P.

As, Q lost by 44 votes,

Vote for P = Vote for Q + 44

Vote for P = 1 + 44

Vote for P = 45

Total no of votes = vote for P + vote for Q

= 45 + 1 = 46

46 is your answer

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