Question

2 - 5) Solve any two of the following.
7 The diameter of the wheel of a tractor is 98 cm. How many
kilometres will it travel in 1000 rotations?
2) The length and breadth of a rectangular plot is 50 m and 40
respectively. It is to be fenced by 5 rounds of a metal wire w
costs 80 rupees per metre. Find the cost of fencing the plot
3) Weight of 36 children in a class is given in kilograms. Draw
frequency table of this data​

Answer 1

Answer:

Step-by-step explanation:

7) Diameter of the wheel of a tractor = 98cm

Therefore, distance covered in one rotation = 98cm

Hence, distance covered in 1000 rotations = 98*1000cm = 98000cm or 980m. (Ans)

3) Length of the rectangular plot = 50m

Breadth of the rectangular plot = 40m

Therefore, perimeter of the rectangular plot = 50*40m = 2000m

So, 2000m of metal wire is required to fence the rectangular plot.

Cost of 1 meter metal wire = Rs.80

Cost of 2000 meter metal wire = Rs.80*2000 = Rs.160000 (Ans)

Here are your answers. Hope it helps!

Answer 2

7) Diameter of the wheel of a tractor = 98cm

Therefore, distance covered in one rotation = 98cm

Hence, distance covered in 1000 rotations = 98*1000cm = 98000cm or 980m. (Ans)

3) Length of the rectangular plot = 50m

Breadth of the rectangular plot = 40m

Therefore, perimeter of the rectangular plot = 50*40m = 2000m

So, 2000m of metal wire is required to fence the rectangular plot.

Cost of 1 meter metal wire = Rs.80

Cost of 2000 meter metal wire = Rs.80*2000 = Rs.160000 (Ans)

Here are your answers. Hope it helps! Plz mark me as Brainliest!!

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