Math, asked by saraswaticlasses276, 4 months ago

2/5. द्विघात बहुपद बनाइए यदि शून्यक 1/3 और 2/5 हैं​

Answers

Answered by narendra30599
0

Answer:

{\large{\boxed{\mathfrak{\red{ {x}^{2}  -   \frac{11}{15}x +  \frac{2}{15} = 0   }}}}}

Step-by-step explanation:

{\small{{\mathtt{\blue{a {x}^{2} + bx + c = 0 }}}}}

=>

{\small{{\mathtt{\blue{{x}^{2} + \frac{b}{a}x   +  \frac{c}{a}  = 0}}}}}

we know that,

{\small{{\mathtt{\green{मूलो\ का\ योग= -b/a}}}}}

-b/a = 1/3 + 2/5 = 11/15

=> b/a = -11/15 ...................(1)

{\small{{\mathtt{\green{मूलो\ का\ गुणनखण्ड= c/a}}}}}

c/a=(1/3)(2/5)=2/15 ..............(2)

then,

{\large{\boxed{\mathtt{\blue{ {x}^{2}  -   \frac{11}{15}x +  \frac{2}{15} = 0   }}}}}

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