Question

(2 ^ - 5) * x = 2 ^ - 1​

Answer 1

Answer:

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Answer 2

Answer:

(2+i)x² - (5-i)x + 2(1 - i) = 0

Math 5 points

from quadratic equation, ax² +

x = [-b ± √(b² - 4ac)}/2a

V

bx + c = 0

so, x= [(5-i) ± √((5 - i)² - 4.2(1 - i).(2+i)}]/

2(2+i)

= [(5 - i) ± √(25 + 1² - 10i - 8(2 + i -2i - i²))]/ 2(2+i)

we know, i² = -1

= [(5-i) ± √(25 -1-10i - 8(2 - i+ 1)]]/2(2+i)

= [(5-i) ± √(24-10i - 24 + 8i]]/2(2 + i)

= [(5-i) ± √(-21]]/2(2 + i)

here, -2i = (1 - i)²

so, √(-21) (1 - i)

so, x= [(5-1) + (1 - i)]/2(2+i)

= (3-1)/(2+i), 2/(2 + i) = (3-1)(2-1)/(2 + i)(2-i), 2(2-1)/(2 + i)

= (1 - i), 2(2- i)/5

= (1 - i), 4/5 - 21/5

hence, there are two values of x

i.e., (1 - i), 4/5 - 21/5

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Step-by-step explanation:

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