Question

2√5=√x^2+73 so find velue of x​

Answer 1

Answer:

x = ± ( $2\sqrt{5} -73$ )

Step-by-step explanation:

We know that $\sqrt{x^{2} } = |x|$

so |x| = $2\sqrt{5} -73$

on opening mod

x = ± ( $2\sqrt{5} -73$ )