Question

2.52,2.5,2.51,2.54,2.49 find mean error absolute eror relative eroor %error

Answer 1

Answer:mean error = 2.5

Absolute error= 0.08

Relative error = 0.03

% error = 3%

Explanation:

Data : 2.52,2.5,2.51,2.54,2.49

Mean : 2.52+2.5+2.51+2.54+2.49 ÷ 5

= 2.512 = 2.51

∆a1= a1 - mean = 0.01

∆a2= a2 - mean = 0.02

∆a3= a3 - mean = 0

∆a4= a4 - mean = 0.03

∆a5= a5 - mean = 0.02

Mean error = 0.08 ÷ 5 = 0.016

Relative error = 0.08÷ 2.51= 0.03

Percentage error = 0.03 × 100 = 3%

Answer 2

Answer:

Values = 2.52, 2.5, 2.51, 2.54, 2.49

The mean value = (2.52 + 2.5 + 2.51 + 2.54 + 2.49)/5

= 12.56/5

= 2.512 or 2.51

Absolute errors:-

• 2.52 - 2.51 = 0.01
• 2.50 - 2.51 = |-0.01| = 0.01
• 2.51 - 2.51 = 0
• 2.54 - 2.51 = 0.03
• 2.49 - 2.51 = |-0.02| = 0.02

Absolute mean error = (0.01 + 0.01 + 0 + 0.03 + 0.02)/5

= 0.07/5

= 7/500

= 0.014

So, the Relative error:- ∆a_mean/a_mean

= 0.01/2.51

= 0.0039

Hence, the percentage error = 0.0039 * 100 = 0.39 = 0.4 %