Question

2.55 2.51 2.49 2.56 2.48 and 2.58 find the percentage error relative error and random error​

Answer 1

Step-by-step explanation:

Average length

=2.48+2.46+2.49+2.50+2.485=12.415m

=2.482m=2.48m(rounded off to 2 places)

Absolute errors id different measurements are ,

Δl1=2.48−2.48=0.00m

Δl2=2.48−2.46=0.02m

Δl3=2.48−2.49=0.01m

Δl4=2.48−2.50=0.02m

Δl5=2.48−2.48=0.00m

Mean absoulte error =Σ|ΔL|5

=0.00+0.02+0.01+0.02+0.005=0.01m

∴ Correct length=(2.48±0.01)m

Percentage error=0.012.48×100=0.40%

Answer

2.48m ; 0.00m, 0.02m, -0.01 m,

-0.02 m, 0.00m; 0.01 m ; 0.40%

please mark me as brainlist please