Math, asked by ahadpadania7526, 1 year ago

2÷56 +[(434-789)×23×5728+8627]

Answers

Answered by fatimawarsi

2÷56+((432-789)×23×5728+8627)

=2÷56+(-357×23×5728+8627)

=2÷56+(-8188×5728+8627)

=2÷56+(-46082064+8627)

=2÷56-4616833

=2÷-4616777

=4.33202643E-7

I don't know if it is correct or not, I am sorry!!

hope it helps you ✌

Previous Question

Next Question

Similar questions

Math, 7 months ago

Hindi, 7 months ago

Math, 7 months ago

Chemistry, 1 year ago

Nuclear reactions accompanied with emission of neutron(s) are : (a) $^{17}_{13}Al + ^4_2H \longrightarrow ^{30}_{15}P$ (b) $^{12}_6C + ^1_1H \longrightarrow ^{13}_7N$ (c) $^{30}_{15}P \longrightarrow ^{30}_{14}Si + ^0_1e$ (d) $^{241}_{96}Am + ^4_2He \longrightarrow ^{244}_{97}Bk + ^0_1e$ ...

English, 1 year ago

Chemistry, 1 year ago

Math, 1 year ago

Math, 1 year ago