Question

ʏᴇʟʟᴏᴡ ʟɪɢʜᴛ ᴇᴍɪᴛᴛᴇᴅ ꜰʀᴏᴍ ᴀ ꜱᴏᴅɪᴜᴍ ʟᴀᴍᴘ ʜᴀꜱ ᴀ ᴡᴀᴠᴇʟᴇɴɢᴛʜ (2) ᴏꜰ 580 ɴᴍ. ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ꜰʀᴇQᴜᴇɴᴄʏ (ᴠ) ᴀɴᴅ ᴡᴀᴠᴇ ɴᴜᴍʙᴇʀ (ᴠ) ᴏꜰ ʏᴇʟʟᴏᴡ ʟɪɢʜᴛ.

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Answer 1

Explanation:

$\lambda = 580nm$

λ = wavelength

Now λν = c

where ν = frequency

and c = speed of light in space/air = $3 \times 10^{8}$

$\lambda = 580 \times 10^{-9} m\\\\v = \frac{c}{\lambda}\\\\v = \frac{3\times10^{8}}{580\times10^{-9}}\\\\v = 5.17 \times 10^{14} Hz$

wave number = $\frac{1}{\lambda}$ = $\bar{v}$

wave number = $\frac{1}{580 \times 10^{-9}} = 0.00172 \times 10^{9} = 1.72 \times 10^{6} m^{-1}$

Answer 2

Answer:

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refer to the attachment sakshi !!

hope it helps uh !!! :)