Question

2.5g of silver carbonate (275g/mol) on being strongly heated yields a residue of Ag weighing ?

Answer 1

$\huge\underline\purple{\sf Answer:-}$

★$\large{\boxed{\sf Ag\:will\: produce\:2.1g}}$

$\huge\underline\purple{\sf Solution:-}$

$\large{\sf 2Ag_{2}CO_{3}→4Ag+2CO_{2}+O_{2}}$

So, on strongly heating silver carbonate will produce silver .

We know that ,

★$\large{\boxed{\sf Mole(n)={\frac{Mass}{Molecular\:Mass}}}}$

Mass (m) of Silver Carbonate is =2.5g (given)

No. of moles of Silver Carbonate =${\sf{\frac{2.5}{275.7}}}$

$\large\implies{\sf 0.009 moles }$

Assume ,

mass of Ag = x

No. of moles of Ag =${\sf {\frac{x}{108}}}$

275 .7 g of $\sf{Ag_{2}CO_{3}}$ produce 108 × 2g of Ag

So ,

2.5 g will produce =${\sf{\frac{108×2×2.76}{275.7}}}$

$\large\implies{\sf {\frac{596.16}{275.7}}}$

★$\large\red{\boxed{\sf Ag\:will\:produce=2.1g}}$