2.5g of solute is dissolved in 25g of water to form the saturated solution at 298 k. Find the solubility of the solute at this temperature.
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Mass of solute /mass of solvent *100=solubility
2.5/25*100=10g
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2.5/25*100=10g
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Answer: The solubility of solute is at the given temperature is 10 g/100 g
Explanation:
Solubility is defined as the amount of solute that can be dissolved in 100 grams of solvent.
We are given:
Amount of solute dissolved in 25 grams of water = 2.5 g
To calculate the mass of solute that can be dissolved in 100 g of water, we use unitary method:
In 25 grams of water, amount of solute dissolved is 2.5 grams
So, in 100 grams of water, amount of solute dissolved will be =
Hence, the solubility of solute at the given temperature is 10 g/100 g
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