Question

-2+5i/3-6i in the form of a+ib​

Answer 1

Answer:

Denomenator canjugate multiple and divide

Answer 2

Answer:

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Step-by-step explanation:

$so \: here \\ - 2 + 5i/3 - 6i \\ so \: conjugate \: of \: \: 3 - 6i \: is \: 3 + 6i \\ so \: by \: conjugate \: method \\ we \: get \\ ( - 2 + 5i/3 - 6i) \times (3 + 6i/3 + 6 i) \\ = - 6 - 12i + 15i + 30i {}^{2} /(3) {}^{2} - (6i) {}^{2} \\ = - 6 + 3i + (30 \times ( - 1))/9 - 36i {}^{2} \\ since \: i {}^{2} = - 1 \\ = - 6 + 3i + ( - 30)/9 - 36( - 1) \\ = - 6 - 30 + 3i/9 - ( - 36) \\ = 3i - 36/(9 + 36) \\ = 3i - 36/45 \\ = 3(i - 12)/45 \\ = i - 12/15 \\ =i / 15 - 12 /15\\ so comparing now \: with \: a + ib \\ we \: get \: then \\ a = - 12/15 \\ b = 1/15 \\ \\ ie \: a = - 4/5 \: \: \: \: b = 1/15$