Question

2 ^{5x}÷ 2^ = \sqrt[5]{2^{20}
$[tex]2 ^{5x}÷ 2^x = \sqrt[5]{2^{20} }$[/tex]
solve to find value suitable for x ​

Answer 1

Answer:

Solve 3{y}^{2}-5y+2=0 by using the Quadratic Formula.

y=\frac{2}{3},y=1

Solve 4{z}^{2}+2z-6=0 by using the Quadratic Formula.

z=-\frac{3}{2},z=1

Step-by-step explanation:

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