Question

2/5x-3/7-1/14-3/7x3/5 using appropriate identities

Answer 1

We have 2/5×−3/7 − 1/4 −3/7 × 3/5

First we apply commutative properties , And get

2/5×−3/7 −3/7 × 3/5− 1/14
Now apply distributive properties and take common −3/7 , As:
⇒ −3/7 ( 2/5 + 3/5 ) −1/14

Now solve using BODMAS properties As:

⇒−3/7 (5/5) −1/14

⇒−3/7−1/14

Take L.C.M. of the denominator terms 7 And 14 that is 14 So

⇒−6/14 − 1/14

⇒−7/14

⇒− 1/2

Answer 2

Answer:

$\frac{2}{5}*\frac{-3}{7}-\frac{1}{14}-\frac{3}{7}*\frac{3}{5}=\frac{-1}{2}$.

Step-by-step explanation:

Given, $\frac{2}{5}*\frac{-3}{7}-\frac{1}{14}-\frac{3}{7}*\frac{3}{5}$

Using commutativity the given expression can be rewritten as:

$\frac{2}{5}*\frac{-3}{7}-\frac{1}{14}-\frac{3}{7}*\frac{3}{5}=\frac{2}{5}*\frac{-3}{7}-\frac{3}{7}*\frac{3}{5}-\frac{1}{14}$

Now taking $\frac{-3}{7}$ from first two terms we get,

$\frac{2}{5}*\frac{-3}{7}-\frac{3}{7}*\frac{3}{5}-\frac{1}{14}=\frac{-3}{7}(\frac{2}{5}+\frac{3}{5} )-\frac{1}{14}$

Using BODMAS rule we simplify this expression.

$\frac{-3}{7}(\frac{2}{5}+\frac{3}{5} )-\frac{1}{14}=-\frac{3}{7} (\frac{5}{5} )-\frac{1}{14}$

                        $=-\frac{3}{7} -\frac{1}{14}\\=\frac{-6-1}{14} \\=\frac{-7}{14}\\=-\frac{1}{2}$                              

Hence the expression $\frac{2}{5}*\frac{-3}{7}-\frac{1}{14}-\frac{3}{7}*\frac{3}{5}=\frac{-1}{2}$.

#SPJ2