Math, asked by aditisingh57, 1 year ago

2/5y - 5/8 y = 5/12 linear​

Answers

Answered by Anonymous
19

Answer:

 \frac{2}{5y}  -  \frac{5}{8y}  =  \frac{5}{12}  \\  \\  \frac{16y - 25y}{40 {y}^{2} }  =  \frac{5}{12}  \\  \\ 12( - 9y) = 40 {y}^{2} (5) \\  \\ -  108y = 200 {y}^{2} \\  \\  - 108y - 200 {y}^{2}  = 0 \\  \\ y(108  +  200y) = 0 \\  \\ 108  +  200y = 0  \:  \:  \:  \: and \:  \: y = 0\\  \\ 200y =  - 108 \\  \\ y =  \frac{ - 108}{200}  \\  \\ y =  \frac{54}{100}  \\  \\ y =  \frac{27}{50}

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