Math, asked by venkat1291, 1 year ago

2(5z-7)+2(92-11)=4(82-7)-111


amritgiri: 10z-14+184-22=328-28-111
amritgiri: 10z+184-36=328-139
amritgiri: 10z+148=289
amritgiri: z=14.1

Answers

Answered by LADHARUPESH
1
(10z-14)+(184-22)=(328-28)-111
10z-14+162=300-111
10z+148=189
10z=41
x=4.1
Answered by ganapathi10031999
0

2(5z-7)+2(92-11)=4(82-7)-111

10z-14+184-22=300-11

10z+148=289

10z=141

z=14.1

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