2(5z-7)+2(92-11)=4(82-7)-111
amritgiri:
10z-14+184-22=328-28-111
Answers
Answered by
1
(10z-14)+(184-22)=(328-28)-111
10z-14+162=300-111
10z+148=189
10z=41
x=4.1
10z-14+162=300-111
10z+148=189
10z=41
x=4.1
Answered by
0
2(5z-7)+2(92-11)=4(82-7)-111
10z-14+184-22=300-11
10z+148=289
10z=141
z=14.1
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