2,6,10,14,18,22,26,30,34,38,42,46,50,54,58 sum of these digits 60 after adding only given digits
Answers
Step-by-step explanation:
How can we get 60 by adding only three numbers out of these: 2, 6, 10, 14, 18, 22, 26, 30, 34, 38, 42, 46, 50, 54, & 58?
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Given numbers are of the form (2k-1)2 for k from 1 to 30.
If we take 3 numbers then they are (2a-1)2, (2b-1)2 and (2b-1)2 for some natural numbers a, b and c between 1 and 30 (both inclusive.
The numbers add up to
(2a-1)2+(2b-1)2+(2c-1)2
=(2a-1+2b-1+2c-1)2
=(2(a+b+c)-3)2
So, we get equation
(2(a+b+c)-3)2=60
=>2(a+b+c)-3=30
=>2(a+b+c)-3=30
=>2(a+b+c)=33
33 being odd, it cannot be double of sum of natural numbers
Ans.: No solution.
Another method:
Each of the numbers leaves remainder 2 when we divided by 4. If we add any two such numbers, we get multiple of 4. If we add another number leaving remainder 2 when divided by 4, new result would give remainder 2 when divided by 2. But 60 is multiple of 4 (remainder 0 when divided by 4).
One more method:
Let us divide the problem into half (I mean half of given numbers and total into half).
Given numbers become 1, 3, 5, …, 29 and total becomes 30.
If we can find 3 odd natural numbers adding to 30, doubling them would make the three numbers from original list adding up to 60.
So we need to find 3 odd numbers adding to 30. We know that odd+odd=even and even+odd=odd. So, three odd numbers cannot be added to 30.
Hence, no solution.
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Step-by-step explanation:
Formula: Sn = n/2(a+l)
Since the common difference is equal, i. e. 4, hence the following numbers are forming an AP.
Therefore, here
a=2 ; l = 58; n = 15.
So putting the values in the formula :
Therefore,
Sn=n/2(a+l)
15/2(2+58)
15/2(60)
15*30
450
Therefore the sum of the given number is 450.
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