2,6,10,14,18,22,26,30,34,38,42,46,50,54,58 then i want answer that pick out any 3 number from this 15 numbers & show the result 60
Answers
Answered by
5
Answer ⇒ There is no solution of the Question.
Explanation ⇒ In the above given numbers there is no set of three numbers from which 60 as the result can obtained. The numbers given above are in the form of 4n + 1, where n can be any number given above. All numbers leaves the remainder of 2 when divided by the 4.But. 60 can be divisible by the 4, so on adding it cannot possible.
Similarly If we will subtracts the numbers too then also we will get 60 as the result.
Hence, the question have the no solution.
Hope it helps.
Answered by
4
The following series can be written as single function value as
f(x)=4x+2
Where the domain of x is 0 to 14
Now as per the request we have to choose any three numbers whose value add upto 60
Let the three numbers be
a,b,c
So substituting in the main equation we get ,
4a +2 +4b +2 +4c+2 =60
4(a+b+c)=60-6
4(a+b+c)=54
(a+b+c)=54/4
Now since we are taking about only whole numbers there is no chance that sum will result in a fractional value of 54/4
That is 13.5
Whole numbers cant have their sum as fraction
Hence there is no solution to this condition
f(x)=4x+2
Where the domain of x is 0 to 14
Now as per the request we have to choose any three numbers whose value add upto 60
Let the three numbers be
a,b,c
So substituting in the main equation we get ,
4a +2 +4b +2 +4c+2 =60
4(a+b+c)=60-6
4(a+b+c)=54
(a+b+c)=54/4
Now since we are taking about only whole numbers there is no chance that sum will result in a fractional value of 54/4
That is 13.5
Whole numbers cant have their sum as fraction
Hence there is no solution to this condition
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