Question

2,6,10,5,9,13,10,14,18,?,?,?​

Answer 1

Answer:

22 ,26 ,30.....

....... answer

Answer 2

The correct question: 2, 6, 10; 5, 9, 13; 10, 14, 18; ?, ?, ?.

(A) 12, 14, 16

(B) 14, 17, 20

(C) 17, 21, 25

(D) 15, 20, 25.

The correct answer is option (C). 17, 21, 25.

Given:

Given, 2, 6, 10; 5, 9, 13; 10, 14, 18; ?, ?, ?.

The first set of numbers = 2, 6, 10.

The second set of numbers = 5, 9, 13.

The third set of numbers = 10, 14, 18.

To Find:

Using the given three sets of numbers, we have to find the fourth set of numbers.

Solution:

Given, 2, 6, 10; 5, 9, 13; 10, 14, 18; ?, ?, ?.

Consider the numbers in the first set.

The common difference between the consecutive numbers = $6-2 = 10-6 = 4.$

Similarly, the common difference between the consecutive numbers of the second and third sets is also 4.

For second set, $9-5 = 13-9 = 4.$

For third set, $14-10=18-14 = 4.$

Now consider the first term of the three sets of numbers.

The difference between the first terms of the first and second sets = $5-2 =3.$

The difference between the first terms of the second and third sets = $10-5=5.$

From this, it is clear that the difference between the first terms of the third and fourth sets will be 7.

∴, The fourth set of numbers = $( 10 + 7), (17 + 4), (21 + 4) = 17, 21, 25.$

i.e., The given series: $2, 6, 10; 5, 9, 13; 10, 14, 18; 17, 21, 25.$

Hence, the correct set of numbers is (C). 17, 21, 25.

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