Question

2.6.10 .......to n factors
- (2n)!
Plz ans fast....​

Answer 1

Answer:

2.6.10.14 ......n

a= 1

n= n

d= 2

An= a+(n-1)d

= 1+(n-1)2

= 2n -1

= 2n (1 . 3 . 5 . 7 ………. 2n-1)

= 2n ( 1.2.3.4.5.6……2n)/2.4.6.8….2n

= 2n (2n!)/ 2n(1.2.3…..n)

=2n/2n (2n!/n!)

= (2n!/n!)

= 2nPn

= (2n!/n!)

= (n+1) (n+2) ……..(n+n)