2√6+2√10+2√15????solve it
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2√6+2√10+2√15=
If value is known or by finding root under for :::√6;√10;√15.......
We can find the value......
Taking 2 common from all the three..
2*(√6+√10+√15)
2*(2.4+3.1+3.8)
2*(9.3)
18.6
Hope it would help u
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