Question

2√6/√2+√3+6√2/√6+√3-8√3/√6+√2

Answer 1

According to given sum

$\frac{2 \sqrt{6} }{ \sqrt{2} } + \sqrt{3} + \frac{6 \sqrt{2} }{ \sqrt{6} } + \sqrt{3} - \frac{8 \sqrt{3} } { \sqrt{6} } + \sqrt{2}$

$2 \sqrt{3} + 2 \sqrt{3} + \sqrt{2} + \frac{6}{ \sqrt{3} } - \frac{8}{ \sqrt{2} }$

$(4\sqrt{18} + \sqrt{12} + 6 \sqrt{2} - 8 \sqrt{3} ) \div \sqrt{6}$

$(12 \sqrt{2} + 2 \sqrt{3} + 6 \sqrt{2} - 8 \sqrt{3} ) \div \sqrt{6}$

$(18 \sqrt{2} - 6 \sqrt{3} ) \div \sqrt{6}$

$\frac{18}{ \sqrt{3} } - \frac{6}{ \sqrt{2} }$

:-)Hope it helps u.