Question

(2 √6-3√2) Square answer me
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Answer 1

$(2\sqrt{6}-3\sqrt{2} )^2\\\\(a-b)^2=a^2+b^2-2ab\\\\(2\sqrt{6}-3\sqrt{2} )^2=(2\sqrt{6})^2+(3\sqrt{2})^2-2*2\sqrt{6}*3\sqrt{2}\\\\= 24 +18-12\sqrt{12}\\\\=42-12\sqrt{12}$