Question

(√2 + √6)(3√6 - 2√3)​

Answer 1

Answer:

$( \sqrt{2} + \sqrt {6} )(3 \sqrt{6} - 2 \sqrt{3} ) \\ = \sqrt{2} (3 \sqrt{6} - 2 \sqrt{3} ) + \sqrt{6} (3 \sqrt{6} - 2 \sqrt{3} ) \\ = 3 \sqrt{12} - 2 \sqrt{6} + 3 \times 6 - 2 \sqrt{18} \\ = 3 \sqrt{4 \times 3} - 2 \sqrt{6} + 18 - 2 \sqrt{9 \times 2} \\ = 3 \times 2 \sqrt{3} - 2 \sqrt{6} + 18 - 2 \times 3 \sqrt{2} \\ = 6 \sqrt{3} - 2 \sqrt{6} + 18 - 6 \sqrt{2} \\ = 2(3 \sqrt{3} - \sqrt{6} + 9 - 3 \sqrt{2} )$