(2,6)÷(4,2)=?? Plzz help me for finding this question
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Answered by
5
Answer :
Here, (2, 6) = 2 + 6i
and (4, 2) = 4 + 6i
Now,
(2, 6) ÷ (4, 2)
= (2 + 6i)/(4 + 2i)
= {(2 + 6i)(4 - 2i)}/{(4 + 2i)(4 - 2i)}
= (8 - 4i + 24i - 12i²)/(16 - 4i²)
= (8 + 20i + 12)/(16 + 4), since i² = - 1
= (20 + 20i)/(20)
= 1 + i
= (1, 1)
#MarkAsBrainliest
Here, (2, 6) = 2 + 6i
and (4, 2) = 4 + 6i
Now,
(2, 6) ÷ (4, 2)
= (2 + 6i)/(4 + 2i)
= {(2 + 6i)(4 - 2i)}/{(4 + 2i)(4 - 2i)}
= (8 - 4i + 24i - 12i²)/(16 - 4i²)
= (8 + 20i + 12)/(16 + 4), since i² = - 1
= (20 + 20i)/(20)
= 1 + i
= (1, 1)
#MarkAsBrainliest
Thxx
Its a right answer
Thxx alot
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Hmm
super bro
Answered by
4
Hi Friend !!!
Here is ur answer !!!
Here, (2,6) = 2+6i
(4,2) = 4+2i
Now, (2+6i)/(4+2i)
= {(2+6i)(4-2i)} / {(4+2i)(4-2i)}
= (8+24i-4i-12i²)/(4²-4i²)
= (8+20i+12)/16+4 as i² = -1
= (20+20i)/20
= 1+i
= (1,1)
Hope it helps u : )
Here is ur answer !!!
Here, (2,6) = 2+6i
(4,2) = 4+2i
Now, (2+6i)/(4+2i)
= {(2+6i)(4-2i)} / {(4+2i)(4-2i)}
= (8+24i-4i-12i²)/(4²-4i²)
= (8+20i+12)/16+4 as i² = -1
= (20+20i)/20
= 1+i
= (1,1)
Hope it helps u : )
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