Question

2*6=98,5*7=320,9*3=144,11*5=?​

Answer 1

Answer:

Step-by-step explanation:

Take first two multiplication

1)2*6=7

On L.H.S it should be 7*1 or 1*7

Here consider 1*7,it can be obtain by

(2–1)*(6+1)=(1*7)

4*2=27

On L.H.S it should be 3*9 ,9*3 or 27*1

Consider 9*3

But if we use above relation

(4–1)*(2+1)=(3*3),this doen’t give excepted product

If we square the first number then

3^2*3 =27

Therefore for first product

If we try (2–1)^2+(6+1)=1*7=7

Similarly for 2nd

(4–1)^2+(2+1)=9*3=27

Using same releation in 3rd one

(7–1)^2+(3+1)=36*4=144

Therefore

(5–1)^2(8+1)=16*9=144.